In chemical bonding, there are some trends that apply to the majority of chemical compounds. One of these is known as the Octet Rule. This rule states that an atom will always attempt to have a full set of eight valence electrons by bonding with other atoms either covalently or ionically. The way that the Octet Rule works varies for different types of compounds, so in this article we will explore the different possibilities in an organized fashion. Overall, the Octet Rule is one of the most important fundamentals of chemical bonding.
The amount of electrons an element will tend to gain or lose depends on the number of electrons in the atom's valence shell. An atom will always try to ionize to its stable state with the transfer of the fewest electrons possible.
Example 1: A fluorine atom can get a full valence shell by either gaining one more electron, or by losing seven electrons. The former requires the transfer of less electrons, so the fluorine atom will try to gain one electron first. Therefore, \(F^{-}\) ions are more common than \(F^{7+}\) ions.
Example 2: A magnesium atom can get a full valence shell bt either losing two electrons, or by gaining six. The former requires the transfer of fewer electrons, so \(Mg^{2+}\) ions are more common than \(Mg^{6-}\) ions.
Example 3: Note that a carbon atom's valence shell has \(4\) electrons. It can either lose four electrons or gain four electrons to get a full valence shell. Note that either transition requires the transfer of the same number of electrons, so which ion results depends on the other chemicals involved. Note that in an ionic compound comprised of a metal and carbon, carbon will form the \(-4\) carbide ion and form compounds such as magnesium carbide \(Mg_2C\) and sodium carbide \(Na_4C\).
Here is a table of the group that a chemical is in and its most common transaction of gaining or losing electrons to gain a full valence shell.
Group Electrons gained/lost
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1 Lose 1 electron
2 Lose 2 electrons
3 Lose 3 electrons
4 Lose 4 electrons/gain 4 electrons, depends on situation
5 Gain 3 electrons
6 Gain 2 electrons
7 Gain 1 electrons
8 These chemicals, known as the noble gases, already have a full valence shell and thus tend to be unreactive (inert).
In an ionic compound, electrons are not shared between ions. Each valence electron is designated to belong to a specific ion in the bond. In a binary ionic compound (one with only two different types of ions), each valence electron belongs to either the cation or anion. When either the cation or anion is polyatomic, it becomes more complicated. We can say that the electron belongs to either the cation or anion, but then we need to determine how it is shared between atoms that comprise the polyatomic ion. We will worry about this special case later.
Example 4: Consider Sodium Chloride, \(NaCl\). Sodium atoms have one valence electron and chlorine atoms have seven. If a single electron is transferred from the sodium atom to the chlorine atom, then we get \(Na^{+}\) and \(Cl^{-}\), two ions in stable states. Thus we only need one of each atom to form this stable ionic compound, and both ions now satisfy the Octet Rule.
Example 5: Consider Aluminum Bromide, \(AlBr_3\). Aluminium is in Group III, and it tends to lose three electrons to form an ion with a full octet (meaning it obeys the Octet Rule). Bromine atoms tend to gain just one electron to get to a full octet, as Bromine is in Group VII. A chemical consisting of an aluminum ion and a bromide ion in their stable states would be \(AlBr^{2+}\), but it is not an ionic compound because it has a charge. Therefore, we need more negatively charged bromide ions to get an ionic compound. Each such ion has a charge of \(-1\), so we need two more to get a neutral compound. Thus aluminum bromide is \(AlBr_3\), with each ion being in its stable octet form.
Example 6: Consider Magnesium Nitride, \(Mg_3N_2\). Magnesium is in Group II and has two electrons in its valence shell. Thus it tends to lose two electrons. In this case, the next set of electrons closer to the nucleus is the new valence shell, and it is full. Nitrogen, on the other hand, is in Group V and has five valence electrons, so it needs to gain three electrons to get a full valence shell. Thus the most stable state for nitrogen ions is the \(N^{3-}\) ion. To find the number of electrons that need transferred