A shop owner wants to prevent shoplifting. He decides to install a security camera on the ceiling of his shop. Below is a picture of the shop floor plan with a square grid. The camera can rotate 360°. The shop owner places the camera at point P, in the corner of the shop.
\(\frac{17}{20} = 0.85\), so 85% of the store is visible, and 15% of the store is hidden from point P.
Case 1: Consider what is hidden from a camera at point Q. If a line is drawn from point Q through point U, it will intersect point W. The area that is hidden is a triangle with area 2 squares. The area visible to the camera at point Q is 18 out of 20 squares.
\(\frac{18}{20} = 0.9\) or 90% of the store is visible, so 10% of the store is hidden from point Q.
If a point is directly below or to the left of Q, then the area that is hidden will be entirely on the right-hand side of the floor plan. If you draw a line from any point that is to the left of Q through point U, the portion of the floor plan that will be hidden will be the region below the line you just drew on the right side of the floor plan (see the figure below for one example).
Case 2: Consider what is hidden from a camera at point R. If a line is drawn from point R through U, it will intersect point V.
The area that is hidden on the right side of the floor plan is a triangle with area 1 square. The same area is hidden on the left side of the store (because the floor plan is symmetrical and R is on the line of symmetry). So there area visible to the camera at point R is 18 out of 20 squares.
\(\frac{18}{20} = 0.9\) or 90% of the store is visible, so 10% of the store is hidden from point R.
What if we put a security camera at any point below R? The part of the floor plan that is hidden in this case will be the region of the floor plan below the lines connecting that point with points T and U. Since those regions will have an area that is greater than the area hidden from point R, point R is a better location for a security camera than any of the ones below R.
Case 3: From point S, exactly the same amount of the store is visible as from point Q above (because the floor plan is symmetrical and Q and S are mirror images). A camera at any point directly below or to the right of S will have a greater amount of the floor plan hidden, just as with all points to the left of point Q.
90% of the store is visible to the camera when it is placed at any one of the points Q, R, or S; from any other area in the store, less than 90% of the store is visible. Assuming the camera is located at the corners of the grid, the best spots to place the camera to prevent shoplifting are at points Q, R, or S.
Commentary
The last question has more than one answer, in the sense that there are three spots that could be considered "best." These three locations all cover the same amount of the store while at the same time miss less of the store than all other possible spots.
A more advanced version of the last question that removes the requirement for the camera to be at a corner of the grid would be appropriate at grade 8 when students are studying parallel lines. Stay tuned for this version of the task.
This task is based on a task developed by the MARS/ Shell Centre team Mathematics Assessment Resource Service. The task is shared with the with attribution, non-commercial, share-alike Creative Commons License.