This headline appeared in a newspaper.
| Every day 7% of Americans eat at Giantburger restaurants |
|---|
Decide whether this headline is true using the following information.
Explain your reasons and show clearly how you figured it out.
If there are about \(8\times 10^3\) Giantburger restaurants in America and each restaurant serves about \(2.5\times10^3\) people every day, then about $$8\times 10^3 \cdot 2.5\times10^3 = 20 \times 10^6 = 2 \times 10^7$$ people eat at a Giantburger restaurant every day.
Since there are about \(3\times10^8\) Americans, the percent of Americans who eat at a Giantburger restaurant every day can be computed by dividing the number of restaurant patrons by the total number of people: $$2 \times 10^7\div 3\times10^8 = \frac23 \times 10^{-1}$$ Since $$\frac23 \times 10^{-1} = \frac23 \times \frac{1}{10} = \frac{2}{30} = \frac{1}{15} = 0.06\overline{6},$$ our estimate is that \(6\frac23 \%\) of Americans eat a Giantburger restaurant every day, which is reasonably close to the claim in the newspaper.